21s^2-23s+2=0

Solution for 21s^2-23s+2=0 equation:

21s^2-23s+2=0

a = 21; b = -23; c = +2;
Δ = b2-4ac
Δ = -232-4·21·2
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-19}{2*21}=\frac{4}{42}
=2/21
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+19}{2*21}=\frac{42}{42}
=1
$